8(x+5)=2(4x+1)+38

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Solution for 8(x+5)=2(4x+1)+38 equation: 


Simplifying
8(x + 5) = 2(4x + 1) + 38

Reorder the terms:
8(5 + x) = 2(4x + 1) + 38
(5 * 8 + x * 8) = 2(4x + 1) + 38
(40 + 8x) = 2(4x + 1) + 38

Reorder the terms:
40 + 8x = 2(1 + 4x) + 38
40 + 8x = (1 * 2 + 4x * 2) + 38
40 + 8x = (2 + 8x) + 38

Reorder the terms:
40 + 8x = 2 + 38 + 8x

Combine like terms: 2 + 38 = 40
40 + 8x = 40 + 8x

Add '-40' to each side of the equation.
40 + -40 + 8x = 40 + -40 + 8x

Combine like terms: 40 + -40 = 0
0 + 8x = 40 + -40 + 8x
8x = 40 + -40 + 8x

Combine like terms: 40 + -40 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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