8(x+56)+2(x-4)=32

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Solution for 8(x+56)+2(x-4)=32 equation: 



8(x+56)+2(x-4)=32

We move all terms to the left:

8(x+56)+2(x-4)-(32)=0

We multiply parentheses

8x+2x+448-8-32=0

We add all the numbers together, and all the variables

10x+408=0

We move all terms containing x to the left, all other terms to the right

10x=-408

x=-408/10

x=-40+4/5

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