8(x+6)+3=-11(x-4)-5

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Solution for 8(x+6)+3=-11(x-4)-5 equation: 



8(x+6)+3=-11(x-4)-5

We move all terms to the left:

8(x+6)+3-(-11(x-4)-5)=0

We multiply parentheses

8x-(-11(x-4)-5)+48+3=0



We calculate terms in parentheses: -(-11(x-4)-5), so:

-11(x-4)-5

We multiply parentheses

-11x+44-5

We add all the numbers together, and all the variables

-11x+39

Back to the equation:

-(-11x+39)



We add all the numbers together, and all the variables

8x-(-11x+39)+51=0

We get rid of parentheses

8x+11x-39+51=0

We add all the numbers together, and all the variables

19x+12=0

We move all terms containing x to the left, all other terms to the right

19x=-12

x=-12/19

x=-12/19

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