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8(x-1)(x-6)=0
We multiply parentheses ..
8(+x^2-6x-1x+6)=0
We multiply parentheses
8x^2-48x-8x+48=0
We add all the numbers together, and all the variables
8x^2-56x+48=0
a = 8; b = -56; c = +48;
Δ = b2-4ac
Δ = -562-4·8·48
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-40}{2*8}=\frac{16}{16} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+40}{2*8}=\frac{96}{16} =6 $
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