8(x-1)+3x-2=5x-1+7(4-2x)

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Solution for 8(x-1)+3x-2=5x-1+7(4-2x) equation:



8(x-1)+3x-2=5x-1+7(4-2x)
We move all terms to the left:
8(x-1)+3x-2-(5x-1+7(4-2x))=0
We add all the numbers together, and all the variables
8(x-1)+3x-(5x-1+7(-2x+4))-2=0
We add all the numbers together, and all the variables
3x+8(x-1)-(5x-1+7(-2x+4))-2=0
We multiply parentheses
3x+8x-(5x-1+7(-2x+4))-8-2=0
We calculate terms in parentheses: -(5x-1+7(-2x+4)), so:
5x-1+7(-2x+4)
determiningTheFunctionDomain 5x+7(-2x+4)-1
We multiply parentheses
5x-14x+28-1
We add all the numbers together, and all the variables
-9x+27
Back to the equation:
-(-9x+27)
We add all the numbers together, and all the variables
11x-(-9x+27)-10=0
We get rid of parentheses
11x+9x-27-10=0
We add all the numbers together, and all the variables
20x-37=0
We move all terms containing x to the left, all other terms to the right
20x=37
x=37/20
x=1+17/20

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