8(x-1)+3x-2=5x-1+7(4-2x)

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Solution for 8(x-1)+3x-2=5x-1+7(4-2x) equation: 



8(x-1)+3x-2=5x-1+7(4-2x)

We move all terms to the left:

8(x-1)+3x-2-(5x-1+7(4-2x))=0

We add all the numbers together, and all the variables

8(x-1)+3x-(5x-1+7(-2x+4))-2=0

We add all the numbers together, and all the variables

3x+8(x-1)-(5x-1+7(-2x+4))-2=0

We multiply parentheses

3x+8x-(5x-1+7(-2x+4))-8-2=0



We calculate terms in parentheses: -(5x-1+7(-2x+4)), so:

5x-1+7(-2x+4)

determiningTheFunctionDomain
5x+7(-2x+4)-1

We multiply parentheses

5x-14x+28-1

We add all the numbers together, and all the variables

-9x+27

Back to the equation:

-(-9x+27)



We add all the numbers together, and all the variables

11x-(-9x+27)-10=0

We get rid of parentheses

11x+9x-27-10=0

We add all the numbers together, and all the variables

20x-37=0

We move all terms containing x to the left, all other terms to the right

20x=37

x=37/20

x=1+17/20

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