8(x-1)-(x-2)=6(x+3)

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Solution for 8(x-1)-(x-2)=6(x+3) equation:



8(x-1)-(x-2)=6(x+3)
We move all terms to the left:
8(x-1)-(x-2)-(6(x+3))=0
We multiply parentheses
8x-(x-2)-(6(x+3))-8=0
We get rid of parentheses
8x-x-(6(x+3))+2-8=0
We calculate terms in parentheses: -(6(x+3)), so:
6(x+3)
We multiply parentheses
6x+18
Back to the equation:
-(6x+18)
We add all the numbers together, and all the variables
7x-(6x+18)-6=0
We get rid of parentheses
7x-6x-18-6=0
We add all the numbers together, and all the variables
x-24=0
We move all terms containing x to the left, all other terms to the right
x=24

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