8(x-1)-2x=-2(1+x)+5x

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Solution for 8(x-1)-2x=-2(1+x)+5x equation: 



8(x-1)-2x=-2(1+x)+5x

We move all terms to the left:

8(x-1)-2x-(-2(1+x)+5x)=0

We add all the numbers together, and all the variables

8(x-1)-2x-(-2(x+1)+5x)=0

We add all the numbers together, and all the variables

-2x+8(x-1)-(-2(x+1)+5x)=0

We multiply parentheses

-2x+8x-(-2(x+1)+5x)-8=0



We calculate terms in parentheses: -(-2(x+1)+5x), so:

-2(x+1)+5x

We add all the numbers together, and all the variables

5x-2(x+1)

We multiply parentheses

5x-2x-2

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

6x-(3x-2)-8=0

We get rid of parentheses

6x-3x+2-8=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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