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8(x-1)-4=2x+6(-2+x)
We move all terms to the left:
8(x-1)-4-(2x+6(-2+x))=0
We add all the numbers together, and all the variables
8(x-1)-(2x+6(x-2))-4=0
We multiply parentheses
8x-(2x+6(x-2))-8-4=0
We calculate terms in parentheses: -(2x+6(x-2)), so:We add all the numbers together, and all the variables
2x+6(x-2)
We multiply parentheses
2x+6x-12
We add all the numbers together, and all the variables
8x-12
Back to the equation:
-(8x-12)
8x-(8x-12)-12=0
We get rid of parentheses
8x-8x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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