8(x-1)-5(x+3)=2(x+8)

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Solution for 8(x-1)-5(x+3)=2(x+8) equation: 



8(x-1)-5(x+3)=2(x+8)

We move all terms to the left:

8(x-1)-5(x+3)-(2(x+8))=0

We multiply parentheses

8x-5x-(2(x+8))-8-15=0



We calculate terms in parentheses: -(2(x+8)), so:

2(x+8)

We multiply parentheses

2x+16

Back to the equation:

-(2x+16)



We add all the numbers together, and all the variables

3x-(2x+16)-23=0

We get rid of parentheses

3x-2x-16-23=0

We add all the numbers together, and all the variables

x-39=0

We move all terms containing x to the left, all other terms to the right

x=39

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