8(x-1)=-7(x+4)+40

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Solution for 8(x-1)=-7(x+4)+40 equation: 



8(x-1)=-7(x+4)+40

We move all terms to the left:

8(x-1)-(-7(x+4)+40)=0

We multiply parentheses

8x-(-7(x+4)+40)-8=0



We calculate terms in parentheses: -(-7(x+4)+40), so:

-7(x+4)+40

We multiply parentheses

-7x-28+40

We add all the numbers together, and all the variables

-7x+12

Back to the equation:

-(-7x+12)



We get rid of parentheses

8x+7x-12-8=0

We add all the numbers together, and all the variables

15x-20=0

We move all terms containing x to the left, all other terms to the right

15x=20

x=20/15

x=1+1/3

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