8(x-1)=4(2-x)+4x

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Solution for 8(x-1)=4(2-x)+4x equation: 



8(x-1)=4(2-x)+4x

We move all terms to the left:

8(x-1)-(4(2-x)+4x)=0

We add all the numbers together, and all the variables

8(x-1)-(4(-1x+2)+4x)=0

We multiply parentheses

8x-(4(-1x+2)+4x)-8=0



We calculate terms in parentheses: -(4(-1x+2)+4x), so:

4(-1x+2)+4x

We add all the numbers together, and all the variables

4x+4(-1x+2)

We multiply parentheses

4x-4x+8

We add all the numbers together, and all the variables

8

Back to the equation:

-(8)



We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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