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8(x-1)=4(3+x)
We move all terms to the left:
8(x-1)-(4(3+x))=0
We add all the numbers together, and all the variables
8(x-1)-(4(x+3))=0
We multiply parentheses
8x-(4(x+3))-8=0
We calculate terms in parentheses: -(4(x+3)), so:We get rid of parentheses
4(x+3)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
8x-4x-12-8=0
We add all the numbers together, and all the variables
4x-20=0
We move all terms containing x to the left, all other terms to the right
4x=20
x=20/4
x=5
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