8(x-12)=-40

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Solution for 8(x-12)=-40 equation: 



8(x-12)=-40

We move all terms to the left:

8(x-12)-(-40)=0

We add all the numbers together, and all the variables

8(x-12)+40=0

We multiply parentheses

8x-96+40=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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