8(x-12)=4+2(x+1)

Solution for 8(x-12)=4+2(x+1) equation:

8(x-12)=4+2(x+1)

We move all terms to the left:

8(x-12)-(4+2(x+1))=0

We multiply parentheses

8x-(4+2(x+1))-96=0


We calculate terms in parentheses: -(4+2(x+1)), so:

4+2(x+1)

determiningTheFunctionDomain
2(x+1)+4

We multiply parentheses

2x+2+4

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)


We get rid of parentheses

8x-2x-6-96=0

We add all the numbers together, and all the variables

6x-102=0

We move all terms containing x to the left, all other terms to the right

6x=102

x=102/6

x=17