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8(x-12)=4+2(x+1)
We move all terms to the left:
8(x-12)-(4+2(x+1))=0
We multiply parentheses
8x-(4+2(x+1))-96=0
We calculate terms in parentheses: -(4+2(x+1)), so:We get rid of parentheses
4+2(x+1)
determiningTheFunctionDomain 2(x+1)+4
We multiply parentheses
2x+2+4
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
8x-2x-6-96=0
We add all the numbers together, and all the variables
6x-102=0
We move all terms containing x to the left, all other terms to the right
6x=102
x=102/6
x=17
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