8(x-2)+10+2x+4-x+2=4(x-2)+2x-x

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Solution for 8(x-2)+10+2x+4-x+2=4(x-2)+2x-x equation:



8(x-2)+10+2x+4-x+2=4(x-2)+2x-x
We move all terms to the left:
8(x-2)+10+2x+4-x+2-(4(x-2)+2x-x)=0
We add all the numbers together, and all the variables
x+8(x-2)-(4(x-2)+2x-x)+16=0
We multiply parentheses
x+8x-(4(x-2)+2x-x)-16+16=0
We calculate terms in parentheses: -(4(x-2)+2x-x), so:
4(x-2)+2x-x
We add all the numbers together, and all the variables
x+4(x-2)
We multiply parentheses
x+4x-8
We add all the numbers together, and all the variables
5x-8
Back to the equation:
-(5x-8)
We add all the numbers together, and all the variables
9x-(5x-8)=0
We get rid of parentheses
9x-5x+8=0
We add all the numbers together, and all the variables
4x+8=0
We move all terms containing x to the left, all other terms to the right
4x=-8
x=-8/4
x=-2

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