8(x-2)+10+2x+4-x+2=4(x-2)+2x-x

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Solution for 8(x-2)+10+2x+4-x+2=4(x-2)+2x-x equation: 



8(x-2)+10+2x+4-x+2=4(x-2)+2x-x

We move all terms to the left:

8(x-2)+10+2x+4-x+2-(4(x-2)+2x-x)=0

We add all the numbers together, and all the variables

x+8(x-2)-(4(x-2)+2x-x)+16=0

We multiply parentheses

x+8x-(4(x-2)+2x-x)-16+16=0



We calculate terms in parentheses: -(4(x-2)+2x-x), so:

4(x-2)+2x-x

We add all the numbers together, and all the variables

x+4(x-2)

We multiply parentheses

x+4x-8

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We add all the numbers together, and all the variables

9x-(5x-8)=0

We get rid of parentheses

9x-5x+8=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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