8(x-2)+1=4(x+2)

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Solution for 8(x-2)+1=4(x+2) equation: 



8(x-2)+1=4(x+2)

We move all terms to the left:

8(x-2)+1-(4(x+2))=0

We multiply parentheses

8x-(4(x+2))-16+1=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

8x-(4x+8)-15=0

We get rid of parentheses

8x-4x-8-15=0

We add all the numbers together, and all the variables

4x-23=0

We move all terms containing x to the left, all other terms to the right

4x=23

x=23/4

x=5+3/4

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