8(x-2)+20=40+x

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Solution for 8(x-2)+20=40+x equation: 



8(x-2)+20=40+x

We move all terms to the left:

8(x-2)+20-(40+x)=0

We add all the numbers together, and all the variables

8(x-2)-(x+40)+20=0

We multiply parentheses

8x-(x+40)-16+20=0

We get rid of parentheses

8x-x-40-16+20=0

We add all the numbers together, and all the variables

7x-36=0

We move all terms containing x to the left, all other terms to the right

7x=36

x=36/7

x=5+1/7

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