8(x-2)+3=2(x+1)+6

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Solution for 8(x-2)+3=2(x+1)+6 equation: 



8(x-2)+3=2(x+1)+6

We move all terms to the left:

8(x-2)+3-(2(x+1)+6)=0

We multiply parentheses

8x-(2(x+1)+6)-16+3=0



We calculate terms in parentheses: -(2(x+1)+6), so:

2(x+1)+6

We multiply parentheses

2x+2+6

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

8x-(2x+8)-13=0

We get rid of parentheses

8x-2x-8-13=0

We add all the numbers together, and all the variables

6x-21=0

We move all terms containing x to the left, all other terms to the right

6x=21

x=21/6

x=3+1/2

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