8(x-2)+4x=10(x+1)

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Solution for 8(x-2)+4x=10(x+1) equation: 



8(x-2)+4x=10(x+1)

We move all terms to the left:

8(x-2)+4x-(10(x+1))=0

We add all the numbers together, and all the variables

4x+8(x-2)-(10(x+1))=0

We multiply parentheses

4x+8x-(10(x+1))-16=0



We calculate terms in parentheses: -(10(x+1)), so:

10(x+1)

We multiply parentheses

10x+10

Back to the equation:

-(10x+10)



We add all the numbers together, and all the variables

12x-(10x+10)-16=0

We get rid of parentheses

12x-10x-10-16=0

We add all the numbers together, and all the variables

2x-26=0

We move all terms containing x to the left, all other terms to the right

2x=26

x=26/2

x=13

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