8(x-2)+x=4(x-3)

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Solution for 8(x-2)+x=4(x-3) equation: 



8(x-2)+x=4(x-3)

We move all terms to the left:

8(x-2)+x-(4(x-3))=0

We add all the numbers together, and all the variables

x+8(x-2)-(4(x-3))=0

We multiply parentheses

x+8x-(4(x-3))-16=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

9x-(4x-12)-16=0

We get rid of parentheses

9x-4x+12-16=0

We add all the numbers together, and all the variables

5x-4=0

We move all terms containing x to the left, all other terms to the right

5x=4

x=4/5

x=4/5

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