8(x-2)-(x+4)=20+x

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Solution for 8(x-2)-(x+4)=20+x equation: 



8(x-2)-(x+4)=20+x

We move all terms to the left:

8(x-2)-(x+4)-(20+x)=0

We add all the numbers together, and all the variables

8(x-2)-(x+4)-(x+20)=0

We multiply parentheses

8x-(x+4)-(x+20)-16=0

We get rid of parentheses

8x-x-x-4-20-16=0

We add all the numbers together, and all the variables

6x-40=0

We move all terms containing x to the left, all other terms to the right

6x=40

x=40/6

x=6+2/3

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