8(x-2)-2(x+4)=10+5(2x-8)

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Solution for 8(x-2)-2(x+4)=10+5(2x-8) equation: 



8(x-2)-2(x+4)=10+5(2x-8)

We move all terms to the left:

8(x-2)-2(x+4)-(10+5(2x-8))=0

We multiply parentheses

8x-2x-(10+5(2x-8))-16-8=0



We calculate terms in parentheses: -(10+5(2x-8)), so:

10+5(2x-8)

determiningTheFunctionDomain
5(2x-8)+10

We multiply parentheses

10x-40+10

We add all the numbers together, and all the variables

10x-30

Back to the equation:

-(10x-30)



We add all the numbers together, and all the variables

6x-(10x-30)-24=0

We get rid of parentheses

6x-10x+30-24=0

We add all the numbers together, and all the variables

-4x+6=0

We move all terms containing x to the left, all other terms to the right

-4x=-6

x=-6/-4

x=1+1/2

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