8(x-2)-3(1-x)=9(x-2)+1

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Solution for 8(x-2)-3(1-x)=9(x-2)+1 equation:



8(x-2)-3(1-x)=9(x-2)+1
We move all terms to the left:
8(x-2)-3(1-x)-(9(x-2)+1)=0
We add all the numbers together, and all the variables
8(x-2)-3(-1x+1)-(9(x-2)+1)=0
We multiply parentheses
8x+3x-(9(x-2)+1)-16-3=0
We calculate terms in parentheses: -(9(x-2)+1), so:
9(x-2)+1
We multiply parentheses
9x-18+1
We add all the numbers together, and all the variables
9x-17
Back to the equation:
-(9x-17)
We add all the numbers together, and all the variables
11x-(9x-17)-19=0
We get rid of parentheses
11x-9x+17-19=0
We add all the numbers together, and all the variables
2x-2=0
We move all terms containing x to the left, all other terms to the right
2x=2
x=2/2
x=1

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