8(x-2)-3(1-x)=9(x-2)+1

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Solution for 8(x-2)-3(1-x)=9(x-2)+1 equation: 



8(x-2)-3(1-x)=9(x-2)+1

We move all terms to the left:

8(x-2)-3(1-x)-(9(x-2)+1)=0

We add all the numbers together, and all the variables

8(x-2)-3(-1x+1)-(9(x-2)+1)=0

We multiply parentheses

8x+3x-(9(x-2)+1)-16-3=0



We calculate terms in parentheses: -(9(x-2)+1), so:

9(x-2)+1

We multiply parentheses

9x-18+1

We add all the numbers together, and all the variables

9x-17

Back to the equation:

-(9x-17)



We add all the numbers together, and all the variables

11x-(9x-17)-19=0

We get rid of parentheses

11x-9x+17-19=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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