8(x-2)-3(2x+1)=7x+4-3(x+1)

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Solution for 8(x-2)-3(2x+1)=7x+4-3(x+1) equation: 



8(x-2)-3(2x+1)=7x+4-3(x+1)

We move all terms to the left:

8(x-2)-3(2x+1)-(7x+4-3(x+1))=0

We multiply parentheses

8x-6x-(7x+4-3(x+1))-16-3=0



We calculate terms in parentheses: -(7x+4-3(x+1)), so:

7x+4-3(x+1)

determiningTheFunctionDomain
7x-3(x+1)+4

We multiply parentheses

7x-3x-3+4

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

2x-(4x+1)-19=0

We get rid of parentheses

2x-4x-1-19=0

We add all the numbers together, and all the variables

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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