8(x-2)-3(2x-4)=2(x+3)

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Solution for 8(x-2)-3(2x-4)=2(x+3) equation:


Simplifying
8(x + -2) + -3(2x + -4) = 2(x + 3)

Reorder the terms:
8(-2 + x) + -3(2x + -4) = 2(x + 3)
(-2 * 8 + x * 8) + -3(2x + -4) = 2(x + 3)
(-16 + 8x) + -3(2x + -4) = 2(x + 3)

Reorder the terms:
-16 + 8x + -3(-4 + 2x) = 2(x + 3)
-16 + 8x + (-4 * -3 + 2x * -3) = 2(x + 3)
-16 + 8x + (12 + -6x) = 2(x + 3)

Reorder the terms:
-16 + 12 + 8x + -6x = 2(x + 3)

Combine like terms: -16 + 12 = -4
-4 + 8x + -6x = 2(x + 3)

Combine like terms: 8x + -6x = 2x
-4 + 2x = 2(x + 3)

Reorder the terms:
-4 + 2x = 2(3 + x)
-4 + 2x = (3 * 2 + x * 2)
-4 + 2x = (6 + 2x)

Add '-2x' to each side of the equation.
-4 + 2x + -2x = 6 + 2x + -2x

Combine like terms: 2x + -2x = 0
-4 + 0 = 6 + 2x + -2x
-4 = 6 + 2x + -2x

Combine like terms: 2x + -2x = 0
-4 = 6 + 0
-4 = 6

Solving
-4 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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