8(x-2)-4x+6=6-2(x+4)+4x

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Solution for 8(x-2)-4x+6=6-2(x+4)+4x equation: 



8(x-2)-4x+6=6-2(x+4)+4x

We move all terms to the left:

8(x-2)-4x+6-(6-2(x+4)+4x)=0

We add all the numbers together, and all the variables

-4x+8(x-2)-(6-2(x+4)+4x)+6=0

We multiply parentheses

-4x+8x-(6-2(x+4)+4x)-16+6=0



We calculate terms in parentheses: -(6-2(x+4)+4x), so:

6-2(x+4)+4x

determiningTheFunctionDomain
-2(x+4)+4x+6

We add all the numbers together, and all the variables

4x-2(x+4)+6

We multiply parentheses

4x-2x-8+6

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

4x-(2x-2)-10=0

We get rid of parentheses

4x-2x+2-10=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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