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8(x-2)3x=61
We move all terms to the left:
8(x-2)3x-(61)=0
We multiply parentheses
24x^2-48x-61=0
a = 24; b = -48; c = -61;
Δ = b2-4ac
Δ = -482-4·24·(-61)
Δ = 8160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8160}=\sqrt{16*510}=\sqrt{16}*\sqrt{510}=4\sqrt{510}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-4\sqrt{510}}{2*24}=\frac{48-4\sqrt{510}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+4\sqrt{510}}{2*24}=\frac{48+4\sqrt{510}}{48} $
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