8(x-2)=-4(x+3)+22

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Solution for 8(x-2)=-4(x+3)+22 equation: 



8(x-2)=-4(x+3)+22

We move all terms to the left:

8(x-2)-(-4(x+3)+22)=0

We multiply parentheses

8x-(-4(x+3)+22)-16=0



We calculate terms in parentheses: -(-4(x+3)+22), so:

-4(x+3)+22

We multiply parentheses

-4x-12+22

We add all the numbers together, and all the variables

-4x+10

Back to the equation:

-(-4x+10)



We get rid of parentheses

8x+4x-10-16=0

We add all the numbers together, and all the variables

12x-26=0

We move all terms containing x to the left, all other terms to the right

12x=26

x=26/12

x=2+1/6

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