8(x-2)=4(2x-4)-3+

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Solution for 8(x-2)=4(2x-4)-3+ equation: 



8(x-2)=4(2x-4)-3+

We move all terms to the left:

8(x-2)-(4(2x-4)-3+)=0

We multiply parentheses

8x-(4(2x-4)-3+)-16=0



We calculate terms in parentheses: -(4(2x-4)-3+), so:

4(2x-4)-3+

We add all the numbers together, and all the variables

4(2x-4)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

8x-8x+16-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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