8(x-2)=9+3(4x+1)

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Solution for 8(x-2)=9+3(4x+1) equation:



8(x-2)=9+3(4x+1)
We move all terms to the left:
8(x-2)-(9+3(4x+1))=0
We multiply parentheses
8x-(9+3(4x+1))-16=0
We calculate terms in parentheses: -(9+3(4x+1)), so:
9+3(4x+1)
determiningTheFunctionDomain 3(4x+1)+9
We multiply parentheses
12x+3+9
We add all the numbers together, and all the variables
12x+12
Back to the equation:
-(12x+12)
We get rid of parentheses
8x-12x-12-16=0
We add all the numbers together, and all the variables
-4x-28=0
We move all terms containing x to the left, all other terms to the right
-4x=28
x=28/-4
x=-7

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