8(x-2)=9+3(4x+1)

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Solution for 8(x-2)=9+3(4x+1) equation: 



8(x-2)=9+3(4x+1)

We move all terms to the left:

8(x-2)-(9+3(4x+1))=0

We multiply parentheses

8x-(9+3(4x+1))-16=0



We calculate terms in parentheses: -(9+3(4x+1)), so:

9+3(4x+1)

determiningTheFunctionDomain
3(4x+1)+9

We multiply parentheses

12x+3+9

We add all the numbers together, and all the variables

12x+12

Back to the equation:

-(12x+12)



We get rid of parentheses

8x-12x-12-16=0

We add all the numbers together, and all the variables

-4x-28=0

We move all terms containing x to the left, all other terms to the right

-4x=28

x=28/-4

x=-7

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