8(x-3)+10=4(x-4)-2

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Solution for 8(x-3)+10=4(x-4)-2 equation: 



8(x-3)+10=4(x-4)-2

We move all terms to the left:

8(x-3)+10-(4(x-4)-2)=0

We multiply parentheses

8x-(4(x-4)-2)-24+10=0



We calculate terms in parentheses: -(4(x-4)-2), so:

4(x-4)-2

We multiply parentheses

4x-16-2

We add all the numbers together, and all the variables

4x-18

Back to the equation:

-(4x-18)



We add all the numbers together, and all the variables

8x-(4x-18)-14=0

We get rid of parentheses

8x-4x+18-14=0

We add all the numbers together, and all the variables

4x+4=0

We move all terms containing x to the left, all other terms to the right

4x=-4

x=-4/4

x=-1

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