8(x-3)+7=(4-17)/2x

Solution for 8(x-3)+7=(4-17)/2x equation:

8(x-3)+7=(4-17)/2x

We move all terms to the left:

8(x-3)+7-((4-17)/2x)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

8(x-3)-((-13)/2x)+7=0

We multiply parentheses

8x-((-13)/2x)-24+7=0

We multiply all the terms by the denominator


8x*2x)-((-13)-24*2x)+7*2x)=0

Wy multiply elements

16x^2-96x^2=0

We add all the numbers together, and all the variables

-80x^2=0

a = -80; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-80)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-160}=0$