8(x-3)+x=6(7-4x)

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Solution for 8(x-3)+x=6(7-4x) equation: 



8(x-3)+x=6(7-4x)

We move all terms to the left:

8(x-3)+x-(6(7-4x))=0

We add all the numbers together, and all the variables

8(x-3)+x-(6(-4x+7))=0

We add all the numbers together, and all the variables

x+8(x-3)-(6(-4x+7))=0

We multiply parentheses

x+8x-(6(-4x+7))-24=0



We calculate terms in parentheses: -(6(-4x+7)), so:

6(-4x+7)

We multiply parentheses

-24x+42

Back to the equation:

-(-24x+42)



We add all the numbers together, and all the variables

9x-(-24x+42)-24=0

We get rid of parentheses

9x+24x-42-24=0

We add all the numbers together, and all the variables

33x-66=0

We move all terms containing x to the left, all other terms to the right

33x=66

x=66/33

x=2

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