8(x-3)-(6+3x)=(-x+2)-5(5-x)

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Solution for 8(x-3)-(6+3x)=(-x+2)-5(5-x) equation: 



8(x-3)-(6+3x)=(-x+2)-5(5-x)

We move all terms to the left:

8(x-3)-(6+3x)-((-x+2)-5(5-x))=0

We add all the numbers together, and all the variables

8(x-3)-(3x+6)-((-1x+2)-5(-1x+5))=0

We multiply parentheses

8x-(3x+6)-((-1x+2)-5(-1x+5))-24=0

We get rid of parentheses

8x-3x-((-1x+2)-5(-1x+5))-6-24=0



We calculate terms in parentheses: -((-1x+2)-5(-1x+5)), so:

(-1x+2)-5(-1x+5)

We multiply parentheses

(-1x+2)+5x-25

We get rid of parentheses

-1x+5x+2-25

We add all the numbers together, and all the variables

4x-23

Back to the equation:

-(4x-23)



We add all the numbers together, and all the variables

5x-(4x-23)-30=0

We get rid of parentheses

5x-4x+23-30=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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