8(x-3)-(6-2x)=2(x+2)-5(6-x)

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Solution for 8(x-3)-(6-2x)=2(x+2)-5(6-x) equation: 



8(x-3)-(6-2x)=2(x+2)-5(6-x)

We move all terms to the left:

8(x-3)-(6-2x)-(2(x+2)-5(6-x))=0

We add all the numbers together, and all the variables

8(x-3)-(-2x+6)-(2(x+2)-5(-1x+6))=0

We multiply parentheses

8x-(-2x+6)-(2(x+2)-5(-1x+6))-24=0

We get rid of parentheses

8x+2x-(2(x+2)-5(-1x+6))-6-24=0



We calculate terms in parentheses: -(2(x+2)-5(-1x+6)), so:

2(x+2)-5(-1x+6)

We multiply parentheses

2x+5x+4-30

We add all the numbers together, and all the variables

7x-26

Back to the equation:

-(7x-26)



We add all the numbers together, and all the variables

10x-(7x-26)-30=0

We get rid of parentheses

10x-7x+26-30=0

We add all the numbers together, and all the variables

3x-4=0

We move all terms containing x to the left, all other terms to the right

3x=4

x=4/3

x=1+1/3

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