8(x-3)-12=6(2x+9)+6

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Solution for 8(x-3)-12=6(2x+9)+6 equation: 



8(x-3)-12=6(2x+9)+6

We move all terms to the left:

8(x-3)-12-(6(2x+9)+6)=0

We multiply parentheses

8x-(6(2x+9)+6)-24-12=0



We calculate terms in parentheses: -(6(2x+9)+6), so:

6(2x+9)+6

We multiply parentheses

12x+54+6

We add all the numbers together, and all the variables

12x+60

Back to the equation:

-(12x+60)



We add all the numbers together, and all the variables

8x-(12x+60)-36=0

We get rid of parentheses

8x-12x-60-36=0

We add all the numbers together, and all the variables

-4x-96=0

We move all terms containing x to the left, all other terms to the right

-4x=96

x=96/-4

x=-24

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