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8(x-3)-2(3-x)=2(x-2)-5(5-x)
We move all terms to the left:
8(x-3)-2(3-x)-(2(x-2)-5(5-x))=0
We add all the numbers together, and all the variables
8(x-3)-2(-1x+3)-(2(x-2)-5(-1x+5))=0
We multiply parentheses
8x+2x-(2(x-2)-5(-1x+5))-24-6=0
We calculate terms in parentheses: -(2(x-2)-5(-1x+5)), so:We add all the numbers together, and all the variables
2(x-2)-5(-1x+5)
We multiply parentheses
2x+5x-4-25
We add all the numbers together, and all the variables
7x-29
Back to the equation:
-(7x-29)
10x-(7x-29)-30=0
We get rid of parentheses
10x-7x+29-30=0
We add all the numbers together, and all the variables
3x-1=0
We move all terms containing x to the left, all other terms to the right
3x=1
x=1/3
x=1/3
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