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8(x-3)-3(x+1)=6x+7-5x
We move all terms to the left:
8(x-3)-3(x+1)-(6x+7-5x)=0
We add all the numbers together, and all the variables
8(x-3)-3(x+1)-(x+7)=0
We multiply parentheses
8x-3x-(x+7)-24-3=0
We get rid of parentheses
8x-3x-x-7-24-3=0
We add all the numbers together, and all the variables
4x-34=0
We move all terms containing x to the left, all other terms to the right
4x=34
x=34/4
x=8+1/2
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