8(x-3)=2(x+1)

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Solution for 8(x-3)=2(x+1) equation: 



8(x-3)=2(x+1)

We move all terms to the left:

8(x-3)-(2(x+1))=0

We multiply parentheses

8x-(2(x+1))-24=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We get rid of parentheses

8x-2x-2-24=0

We add all the numbers together, and all the variables

6x-26=0

We move all terms containing x to the left, all other terms to the right

6x=26

x=26/6

x=4+1/3

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