8(x-4)+(5-x)=0

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Solution for 8(x-4)+(5-x)=0 equation: 



8(x-4)+(5-x)=0

We add all the numbers together, and all the variables

8(x-4)+(-1x+5)=0

We multiply parentheses

8x+(-1x+5)-32=0

We get rid of parentheses

8x-1x+5-32=0

We add all the numbers together, and all the variables

7x-27=0

We move all terms containing x to the left, all other terms to the right

7x=27

x=27/7

x=3+6/7

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