8(x-4)+15=7x-3

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Solution for 8(x-4)+15=7x-3 equation: 



8(x-4)+15=7x-3

We move all terms to the left:

8(x-4)+15-(7x-3)=0

We multiply parentheses

8x-(7x-3)-32+15=0

We get rid of parentheses

8x-7x+3-32+15=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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