8(x-4)+2(x-4)=6(x-4)

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Solution for 8(x-4)+2(x-4)=6(x-4) equation: 



8(x-4)+2(x-4)=6(x-4)

We move all terms to the left:

8(x-4)+2(x-4)-(6(x-4))=0

We multiply parentheses

8x+2x-(6(x-4))-32-8=0



We calculate terms in parentheses: -(6(x-4)), so:

6(x-4)

We multiply parentheses

6x-24

Back to the equation:

-(6x-24)



We add all the numbers together, and all the variables

10x-(6x-24)-40=0

We get rid of parentheses

10x-6x+24-40=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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