8(x-4)+3=2x+6(-5+x)

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Solution for 8(x-4)+3=2x+6(-5+x) equation: 



8(x-4)+3=2x+6(-5+x)

We move all terms to the left:

8(x-4)+3-(2x+6(-5+x))=0

We add all the numbers together, and all the variables

8(x-4)-(2x+6(x-5))+3=0

We multiply parentheses

8x-(2x+6(x-5))-32+3=0



We calculate terms in parentheses: -(2x+6(x-5)), so:

2x+6(x-5)

We multiply parentheses

2x+6x-30

We add all the numbers together, and all the variables

8x-30

Back to the equation:

-(8x-30)



We add all the numbers together, and all the variables

8x-(8x-30)-29=0

We get rid of parentheses

8x-8x+30-29=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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