8(x-4)+4(x+3)=1

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Solution for 8(x-4)+4(x+3)=1 equation:



8(x-4)+4(x+3)=1
We move all terms to the left:
8(x-4)+4(x+3)-(1)=0
We multiply parentheses
8x+4x-32+12-1=0
We add all the numbers together, and all the variables
12x-21=0
We move all terms containing x to the left, all other terms to the right
12x=21
x=21/12
x=1+3/4

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