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8(x-4)-25=2(x+4)
We move all terms to the left:
8(x-4)-25-(2(x+4))=0
We multiply parentheses
8x-(2(x+4))-32-25=0
We calculate terms in parentheses: -(2(x+4)), so:We add all the numbers together, and all the variables
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
8x-(2x+8)-57=0
We get rid of parentheses
8x-2x-8-57=0
We add all the numbers together, and all the variables
6x-65=0
We move all terms containing x to the left, all other terms to the right
6x=65
x=65/6
x=10+5/6
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