8(x-4)-3(x-4)=5(x-4)+x

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Solution for 8(x-4)-3(x-4)=5(x-4)+x equation: 



8(x-4)-3(x-4)=5(x-4)+x

We move all terms to the left:

8(x-4)-3(x-4)-(5(x-4)+x)=0

We multiply parentheses

8x-3x-(5(x-4)+x)-32+12=0



We calculate terms in parentheses: -(5(x-4)+x), so:

5(x-4)+x

We add all the numbers together, and all the variables

x+5(x-4)

We multiply parentheses

x+5x-20

We add all the numbers together, and all the variables

6x-20

Back to the equation:

-(6x-20)



We add all the numbers together, and all the variables

5x-(6x-20)-20=0

We get rid of parentheses

5x-6x+20-20=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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