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8(x-4)-5x=5(2x-3)+4
We move all terms to the left:
8(x-4)-5x-(5(2x-3)+4)=0
We add all the numbers together, and all the variables
-5x+8(x-4)-(5(2x-3)+4)=0
We multiply parentheses
-5x+8x-(5(2x-3)+4)-32=0
We calculate terms in parentheses: -(5(2x-3)+4), so:We add all the numbers together, and all the variables
5(2x-3)+4
We multiply parentheses
10x-15+4
We add all the numbers together, and all the variables
10x-11
Back to the equation:
-(10x-11)
3x-(10x-11)-32=0
We get rid of parentheses
3x-10x+11-32=0
We add all the numbers together, and all the variables
-7x-21=0
We move all terms containing x to the left, all other terms to the right
-7x=21
x=21/-7
x=-3
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