8(x-4)-7=-(x-3)

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Solution for 8(x-4)-7=-(x-3) equation: 



8(x-4)-7=-(x-3)

We move all terms to the left:

8(x-4)-7-(-(x-3))=0

We multiply parentheses

8x-(-(x-3))-32-7=0



We calculate terms in parentheses: -(-(x-3)), so:

-(x-3)

We get rid of parentheses

-x+3

We add all the numbers together, and all the variables

-1x+3

Back to the equation:

-(-1x+3)



We add all the numbers together, and all the variables

8x-(-1x+3)-39=0

We get rid of parentheses

8x+1x-3-39=0

We add all the numbers together, and all the variables

9x-42=0

We move all terms containing x to the left, all other terms to the right

9x=42

x=42/9

x=4+2/3

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