8(x-4)=-4(x+3)+43

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Solution for 8(x-4)=-4(x+3)+43 equation:



8(x-4)=-4(x+3)+43
We move all terms to the left:
8(x-4)-(-4(x+3)+43)=0
We multiply parentheses
8x-(-4(x+3)+43)-32=0
We calculate terms in parentheses: -(-4(x+3)+43), so:
-4(x+3)+43
We multiply parentheses
-4x-12+43
We add all the numbers together, and all the variables
-4x+31
Back to the equation:
-(-4x+31)
We get rid of parentheses
8x+4x-31-32=0
We add all the numbers together, and all the variables
12x-63=0
We move all terms containing x to the left, all other terms to the right
12x=63
x=63/12
x=5+1/4

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