8(x-4)=-7(x+2)+17

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Solution for 8(x-4)=-7(x+2)+17 equation: 



8(x-4)=-7(x+2)+17

We move all terms to the left:

8(x-4)-(-7(x+2)+17)=0

We multiply parentheses

8x-(-7(x+2)+17)-32=0



We calculate terms in parentheses: -(-7(x+2)+17), so:

-7(x+2)+17

We multiply parentheses

-7x-14+17

We add all the numbers together, and all the variables

-7x+3

Back to the equation:

-(-7x+3)



We get rid of parentheses

8x+7x-3-32=0

We add all the numbers together, and all the variables

15x-35=0

We move all terms containing x to the left, all other terms to the right

15x=35

x=35/15

x=2+1/3

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